I can't speak for anything other than PHP and JavaScript (I know, I know... extremely ugly languages), but they both use the same symbol to represent what we know in Perl as scalars, lists, and hashes.

I also could add that this allows for extremely messy and poor practices in code. I've seen this many times:
<?php $foo = 'bar'; $foo['bar'] = 'ding'; ?>

I'm assuming (as I've never looked at the PHP source code) that there are actually two separate variables here, one an array and one a scalar. But then, what happens when you try to do "if ($foo)"?

Naming two variables the same, @foo and $foo, isn't the best practice in Perl, but at least it's possible ;) .

In reply to Re^2: What is the difference between $array[1] and @array[1]? by salazar
in thread What is the difference between $array[1] and @array[1]? by vinoth.ree

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