If GCD(X, Y) <> 1, then any value of T can be obtained provided that T > X*Y - X - Y
I think your condition is not stated correctly. If X = 2 and Y = 4, then no odd T is achievable. Perhaps the condition should be any T where T is a multiple of GCD(X, Y)? </nitpick> And on to the list.
It seems like dynamic programming is the way to go for either optimization. Essentially I see it in two stages: determining algorithms for obtaining all water amounts less than the bigger jug and then application of the Knapsack problem. I'm gonna go off with a pen and paper to think about how to achieve that first part. Don't tell my boss.
In reply to Re: Challenge: N Jugs Problem
by kennethk
in thread Challenge: N Jugs Problem
by Limbic~Region
| For: | Use: | ||
| & | & | ||
| < | < | ||
| > | > | ||
| [ | [ | ||
| ] | ] |