use strict;
use warnings;

my ($a, $b) = ("1_334", 1334);

$a += 1;
$b += 1;
print "$a $b\n";

print "Unequal\n" if ($a != $b);
print "$a $b\n";

[download]
I got the output: 
2 1335
Argument "1_334" isn't numeric in addition (+) at noname.pl line 6.
Unequal
2 1335

[download]
My question is if $a has already become 2, why does the comparison see "1_334". Also I would have thought that the numeric operator would have considered it as a string (in which case $a should have been 0+1) and evaluated to 1 or as a number 1334 and evaluated to 1335; either way being coverted to a number...

In reply to _ in a number within quotes by dilpane

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