Yes, that's it -- don't know why I couldn't see it. However, aarrgghh, I don't see an obvious fix for this that doesn't rely on fn() knowing how it's called or the caller (in the outer substitution) knowing how fn() is going to use its argument list. It seems very unnatural to write s/(x)/fn "$1"/e (with quotes around the argument) and it seems equally unnatural to write the body of fn() any differently (by making a copy of $_[0] before performing the substitution. In general, I certainly don't expect that the argument list to a function will be changed merely by doing something as innocuous as performing substitution on a local string.

I virtually never use fn("$var") instead of fn($var), but I guess if var is a global, including $1, $2, etc, then the safest thing to do is wrap it in quotes to copy the value.

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