Assuming ...
- File #1 always contains the same number of field per record
- You're using *NIX
- You only need to create an output file from the conjoined files
Then
join(1) and
sort(1) are your friends e.g.
sort file1 > file1.sorted
sort file2 | join -1 10 -2 1 file1.sorted - | tee file3
e.g. :
$ echo "SimpsonH","Homer","Simpson","NULL","648","0","218 555","Nuclea
+r Control","Nuclear Operator","111" > file1
$ echo "111","BurnsM" > file2
$ join -t, -1 10 -2 1 file1 file2
111,SimpsonH,Homer,Simpson,NULL,648,0,218 555,Nuclear Control,Nuclear
+Operator,BurnsM
as required
A user level that continues to overstate my experience :-))
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