Dear PerlMonks,
I am trying to convert 32 bit binary number to Hex
Here is the code: 
use strict;
use warnings;
my $bin_val;
my $dec_val;
my @temp_reference_value = ("11111111111111111111111111111111", "11111
+11111111111111111111111111");

for(my $i=0; $i<=$#temp_reference_value; $i++ )
{
    $dec_val = oct("$temp_reference_value[$i]");
    $bin_val = sprintf('0x%x', $dec_val) if($dec_val); 
    print "Bin value $temp_reference_value[$i] and Hex value is $bin_v
+al \n"; 
}

[download]
The error message that i am receiving is 
Integer overflow in octal number at bintohex.pl line 11.
Octal number > 037777777777 non-portable at bintohex.pl line 11.
Bin value 11111111111111111111111111111111 and Hex value is 0xffffffff
Integer overflow in octal number at bintohex.pl line 11.
Octal number > 037777777777 non-portable at bintohex.pl line 11.
Bin value 1111111111111111111111111111111 and Hex value is 0xffffffff

[download]
Hence request your inputs in resolving this issue.

In reply to Integer overflow in octal number by Anonymous Monk

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