Dear Monks,

here is a small new game someone proposed : The Kember identity.
It proposes a funny challenge : programmatically find a chain whose MD5 is itself. I don't know if it's even possible, but here's my try, submit yours :) 

#!/usr/bin/perl


use strict;
use warnings;
use Digest::MD5 qw( md5_hex);                   

for ( my $i=0; $i<340282366920938463463374607431768211455; $i++ ) {
    my $plain = sprintf "%032x", $i;
    my $digest =md5_hex($plain);

    #print "$i $plain $digest\n";

    if ( $plain eq $digest ) {
        print "Winner : $plain \n";
        last
    }

    if ( "$i" =~ m/.*00000$/ ) {
        print "$plain  $digest\n";
    }    
}

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In reply to A small game : Kember identity by wazoox

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