You can always range :)echo Range iterator outside integer range|splain Range iterator outside integer range (#1) (F) One (or both) of the numeric arguments to the range operator " +.." are outside the range which can be represented by integers interna +lly. One possible workaround is to force Perl to use magical string inc +rement by prepending "0" to your numbers.
sub range { my( $start, $end ) = @_; my @ret; while($start <= $end ){ push @ret, $start; $start++; } return @ret; } use bignum; my $x = 2**1024 for(range( $x , $x+2 )) { say }
In reply to Re: big integers forcing me to be a C programmer: "range iterator outside integer range"
by Anonymous Monk
in thread big integers forcing me to be a C programmer: "range iterator outside integer range"
by Boldra
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