This is the code from perlfaq4, and it also says
It assumes that each element is unique in a given array

Is that the case for your arrays? If not, it would explain the difference.

Update: See almut's reply below, this code is nonesense.

(Update:) I'd just store one array in the hash, something along these lines: (untested)

my (@intersection, @union); my %count; @count{@array1} = undef; for (@array2) { if (exists $count{$_}) { push @union, $_; } else { push @intersection, $_; } }

(Second update): Any idea why the answer in the FAQs makes such an IMHO needless assumption? The code without that assumption isn't much longer, and although I haven't benchmarked it I don't think it's much slower either (I even think it uses less memory).


In reply to Re: Difference of array by moritz
in thread Difference of array by sandy1028

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