I came up with this. It's less code than yours (well, if you spread your code out a bit :), but it's actually a bit slower, in benchmarking. So there may be better ways of going about it. 
#!/usr/local/bin/perl -w
use strict;

my %count;

s/([a-zA-Z])/{ $count{lc $1}++; $1 }/eg
    while <>;

for my $letter (sort keys %count) {
    print $letter, "=", $count{$letter}, "\n";
}

[download]
It works by finding a letter ("a-zA-Z"), lower-casing it, and increasing the count of that letter; and it does so for each letter that it finds.

In reply to Re: How To Do This Better? by btrott
in thread How To Do This Better? by buzzcutbuddha

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