Dear Monks,

When I run the following snippet, I got the output as,56555.

#!/usr/bin/perl
use strict;
use warnings;

$a=5;
printf("%d%d%d%d%d\n",$a++,$a--,++$a,--$a,$a);

[download]

In "perlop" man page, I read, there is no associative for '++' and '--' operator. I confused how this program working or executing?. When I run the same program in C, I got, 45555. Please explain how it is working?

Also I have a doubt "If the operator don't have any associative, how Perl will do that operation?."

Is there any side effect If I use same kind of operations?

In reply to Operator Associative in Perl by irah

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