I just got done writing a method to compare two dates. The purpose of the function is to return 1 if the first date is greater than the second (further in the future) and 0 otherwise. The two dates are passed to a subroutine in the following format:
[M]M/[D]D/YYYY
The elements within [] are optional characters. For example, 1/1/2001 would be legal, as would 12/12/2001, but not, 12/12/01. The year requires all four digits.

This is the function I came up with, but I just feel that there must be an easier way to accomplish this task.
sub isGreater { my $currDate = $_[0]; my $oldDate = $_[1]; my $currMonth = substr($currDate, 0, index($currDate, "\/")); $currDate = substr($currDate, index($currDate, "\/")+1); my $oldMonth = substr($oldDate, 0, index($oldDate, "\/")); $oldDate = substr($oldDate, index($oldDate, "\/")+1); my $currDay = substr($currDate, 0, index($currDate, "\/")); $currDate = substr($currDate, index($currDate, "\/")+1); my $oldDay = substr($oldDate, 0, index($oldDate, "\/")); $oldDate = substr($oldDate, index($oldDate, "\/")+1); my $currYear = $currDate; my $oldYear = $oldDate; if ( $currYear > $oldYear ) { return 1; } elsif ( $currMonth > $oldMonth ) { return 1; } elsif ( $currDay > $oldDay ) { return 1; } return 0; }
As you can see, I'm simply grabbing all the characters up to a "/" and then I go back and cut off the front of the date up to (and including that "/"). Simply put, I grab the month from $oldDate, store it into $oldMonth, and then modify $oldDate to go from MM/DD/YYYY to DD/YYYY. For example, if $oldDate contained 1/12/2001, $oldMonth would contain 1 and $oldDate would contain 12/2001.

This method works fine (as far as I can tell - I'm sure it could use more testing), but is there an easier way to pull this off? I'm not overly familiar with Perl and I wonder if there is a built in function to do something quite similar to what I'm doing here.

Thanks,
- Sherlock

In reply to Is there an easier way? by Sherlock

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