Any "word" that can be interpreted as a number will be converted to a string after evaluating its numeric value (e.g. "1.20" and "-034" to the left of "=>" will yield the strings "1.2" and "-34", respectively).
No, it doesn't. 
perl -MDevel::Peek -we '@f = (1.20 => "1.2"); Dump $f[0]; Dump $f[1]'
SV = NV(0x88238e8) at 0x87fc230
  REFCNT = 1
  FLAGS = (NOK,pNOK)
  NV = 1.2
SV = PV(0x87f9044) at 0x87fc424
  REFCNT = 1
  FLAGS = (POK,pPOK)
  PV = 0x8806fc8 "1.2"\0
  CUR = 3
  LEN = 4

[download]
As you can see, the 1.20 is not a string (there's no PV value, nor is POK or pPOK set), while "1.2" is a string (and not a number).

In reply to Re^2: Clarifying the Comma Operator by JavaFan
in thread Clarifying the Comma Operator by ig

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