Great, I think I am getting it somehow, albeit in a random way... I can summarize this as follows 
#working in octets of bits.

01-shift $! bits to the right. #zeroing on target
02-spread &ing carpet under the target #2**(No.of bits)

#carpet size is (1,4,8,16,32) that covers 1,2,3,4..etc bits

#from the second bit the relation is (2**2, 2**3, #2**4...2**32) i.e. 
+2**(bit position).
 
03-&ing makes us extract the bits we want
#(shifted bits)*(appropriate carpet size)=(C or SSs or EEs)

[download]
does this seem all there is to it??? p.s. I don't know anything about carpets by the way except that they are spread or pinned on to a wall

In reply to Re^4: Shift Operators And Bitwise Operators by biohisham
in thread Shift Operators And Bitwise Operators by biohisham

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