The 2nd iteration through the 'for' loop, $i is set to 0.01, which is a floating point value. If you want to control the output, you can use printf: 
perl -e 'for($i=0;$i<10;$i+=0.01){printf "%.2f\n", $i}'
...
9.97
9.98
9.99

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In reply to Re: quick question,why int turns to float by toolic
in thread quick question,why int turns to float by fnever

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