In the code below I would like the Hash filled in the subroutine FillHashOne() to be accessible as a reference in $Hash. However all I get is an empty hash ref.

I think I am missing the section of my brain that is needed to understand references. I have read all the tutorials and have used references many times, but then I run into a situation like this that stymies me.

All help and suggestions are appreciated!

Update: Duh! I messed up my closure and had it inside the subroutine. It works when I fixed that.

#!/usr/bin/perl use strict; use warnings; use constant false => 0; use constant true => 1; $| = true; use Data::Dumper; my $Hash = {}; sub FillHashOne { my %HashOne; { my ($Key, $Value) = @_; if(!defined($Key)) { return(\%HashOne); } else { $HashOne{$Key} = $Value; } } } $Data::Dumper::Indent = 3; $Data::Dumper::Purity = true; $Data::Dumper::Varname = 'Hash'; $Data::Dumper::Quotekeys = true; $Hash->{'One'} = 1; $Hash->{'Two'} = 2; $Hash->{'Three'} = 3; $Hash->{'String'} = 'Foo Bar'; print __LINE__ . ":Main:\$Hash:\n" . Dumper($Hash); for (my $i = 0; $i < 10; $i++) { FillHashOne($i, "Value:\[$i\]"); } $Hash->{'HashOne'} = FillHashOne(undef()); print __LINE__ . ":Main:\$Hash:\n" . Dumper($Hash);


Updated Code:

#!/usr/bin/perl use strict; use warnings; use constant false => 0; use constant true => 1; $| = true; use Data::Dumper; my $Hash = {}; { my %HashOne; sub FillHashOne { my ($Key, $Value) = @_; if(!defined($Key)) { return(\%HashOne); } else { $HashOne{$Key} = $Value; } } } $Data::Dumper::Indent = 3; $Data::Dumper::Purity = true; $Data::Dumper::Varname = 'Hash'; $Data::Dumper::Quotekeys = true; $Hash->{'One'} = 1; $Hash->{'Two'} = 2; $Hash->{'Three'} = 3; $Hash->{'String'} = 'Foo Bar'; print __LINE__ . ":Main:\$Hash:\n" . Dumper($Hash); for (my $i = 0; $i < 10; $i++) { FillHashOne($i, "Value:\[$i\]"); } $Hash->{'HashOne'} = FillHashOne(undef()); print __LINE__ . ":Main:\$Hash:\n" . Dumper($Hash);

In reply to Not So Complex Hash Question by NateTut

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