If a player were to keep rolling the same number, where would they wind up?
As the board is a finite size, there's only two possible kinds of answer, they'd wind up going round in circles, or they'd get to the end and (as this is a game for one) win.
For example, if a player keeps rolling 1, then they'd get into a loop involving ladder 28=>84 and snake/chute 87=>24. (Caution: calculated using head, not Perl.)
So what are the results for rolling only 2s .. 6s? Is it possible to win the game? Which number results in the most convoluted loop? Which number carries on longest before it gets into a loop.
Grr - damn this paid employment lark! I have to stop before I can actually try any of this stuff out!
--
use JAPH;
print JAPH::asString();
In reply to Re: Dial up some obscure stats for the Chutes and Ladders game
by wol
in thread Dial up some obscure stats for the Chutes and Ladders game
by toolic
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