foo doesn't see the $foo you are assigning 1 to. It sees the $foo you are assigning 2 to, but at that time, it's still uninitialized.

my always creates a new variable. The creation of the variable is done at compile time (and hence, at that time it's "decided" which variable a line of code "sees"); the initialization is done run time.

In reply to Re: What is it I don't understand about perl scoping? by JavaFan
in thread What is it I don't understand about perl scoping? by brycen

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