The behaviour of \w shouldn't change based on whether it's in a char class or not.

But running with -Dr shows that these regexes compiled differently. And it looks like the problem is not in IO, I've tried the following:

#use locale; use utf8; $a = 'é'; $a =~ m/\w/ and print "first re match\n"; $a =~ m/[\w]/ and print "second re match\n";
if use locale is commented out it outputs:
first re match second re match
if use locale uncommented only:
second re match
My locale en_US.UTF-8 BTW.

debugperl -Dr shows the following:

Without locale: Compiling REx "\w" Final program: 1: ALNUM (2) 2: END (0) stclass ALNUM minlen 1 Compiling REx "[\w]" Final program: 1: ANYOF[0-9A-Z_a-z+utf8::IsWord] (13) 13: END (0) stclass ANYOF[0-9A-Z_a-z+utf8::IsWord] minlen 1 with locale: Compiling REx "\w" Final program: 1: ALNUML (2) 2: END (0) stclass ALNUML minlen 1 Compiling REx "[\w]" Final program: 1: ANYOF{loc}[\w+utf8::IsWord] (13) 13: END (0) stclass ANYOF{loc}[\w+utf8::IsWord] minlen 1

I don't really understand this output very well, but it looks like it treats this regexes differently.


In reply to Re^3: use locale behavior depends on charset of locale? by zwon
in thread use locale behavior depends on charset of locale? by Anonymous Monk

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