exactly, but that's different from "evaluating in scalar context".

like in $foo=\@bar, $foo is not the length of @bar!

IIRC in Perl 6 there is less confusion, since the scalar of an array is the array-reference.

Cheers Rolf

In reply to Re^5: Scalar Vs. List context by LanX
in thread Scalar Vs. List context by biohisham

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