not easily, since they all do quite different things... much easier as you have it, but if you are diong them often maybe you should look into using qr{} to precompile the regexps...

also, you realize that $print =~ s/([a,e,O])I/\1j/g; matches , as well as a e and O? if you don't want to match comma use [aeO] [] is a character class, so it looks at characters, so a separator is not necessary.

also I believe that using $1 in the second half of the substitution is preferred to \1... perl -w would tell you that...

you can do $print =~ s/([b-zA-Z]):/\1/g; which should be much faster than $print =~ s/([b-z]|[A-Z]):/\1/g; character classes can have as many ranges as you want in them.... but the (|) will slow you down compared to a straight character class...

Update Oops... 9|3: does match 9 or 3:... my bad, ignore the next line
not sure, do you want 9|3: to match '9|3:' or do you want it to match '9' or '3:'... it will match the former...
                - Ant

In reply to Re: Concatenating regexs? by suaveant
in thread Concatenating regexs? by Micz

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