Methinx you could use rudimentary algebraic methods to arrive at your goal, consider: 
@array1=qw(A B C);
@array2=qw(1 2 3);

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is equivalent to/can be re-written as: 
@array1=('A', 'B', 'C');
@array2=('1', '2', '3');

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Also, the requirement can be re-written as: 
%hash = (
array1=>[('A','B','C')],
array2=>[('1','2','3')]
};

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So, substituting for ('A','B','C') & ('1','2','3'), into the re-written required result, gives: 
%hash = (
array1=>[@array1],
array2=>[@array2]
};

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But, [@array] can be/usually is written as \@array, hence, 
%hash = (
array1=>\@array1,
array2=>\@array2
};

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As required - also discoverable by reference to perlreftut - as moritz has previously suggested.

A user level that continues to overstate my experience :-))

In reply to Re: Two arrays into hash by Bloodnok
in thread Two arrays into hash by Anonymous Monk

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