this code would work fine even if that caller assignment in list context is commmented out since caller works in list and scalar context as well. in the second code however, the problem arises since I am putting a subroutine call inside a subroutine of its own, and the same exact code is here in the book and the return value is supposed be so I am wondering if there is something different 
the-calling-subroutine-name
main, directory/program.pl,line,main::the-calling-subroutine-name

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#works fine
sub addem{
        ($value1, $value2)=@_;
        $value1+$value2;
        print join(':',caller);     
#       ($package, $filename, $line)=caller; 
        }

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even this code works fine if I am not calling from within a subroutine the addem() function, 
#notice disablement of the blocks in the callingfun() makes it work
sub addem{
        ($value1,$value2)=@_;
        $value1+$value2;
        print join(',',caller);
        }
#sub callingfun{
       $result = addem(2,2);
#       }

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so I don't really understand the behavior, tried getting a diagnosis using eval function but did not work out..........
Excellence is an Endeavor of Persistence. Chance Favors a Prepared Mind

In reply to Re^2: getting a subroutine's name by biohisham
in thread getting a subroutine's name by biohisham

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