From the "perlfunc" manual description of split:

... If PATTERN is ... omitted, splits on whitespace (after skipping any leading whitespace)... {3rd paragraph}

...

As a special case, specifying a PATTERN of space (’ ’) will split on white space just as "split" with no arguments does. Thus, "split(’ ’)" can be used to emulate awk’s default behavior, whereas "split(/ /)" will give you as many null initial fields as there are leading spaces. A "split" on "/\s+/" is like a "split(’ ’)" except that any leading whitespace produces a null first field. A "split" with no arguments really does a "split(’ ’, $_)" internally. {about 7 paragraphs further down}

In reply to Re^3: New Problem by graff
in thread Tagging the last elements by crochunter

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