It appears to be possible by messing with the opcode tree (based on what Data::Alias is capable of doing), but it's not possible in Perl.

Update: The following would also do if you could localise through a reference: 

sub lambda {
    my $f = $_[1];
    my $xr = \$_[0];
    return sub {
        local $$xr = $_[0];
        return $f->();
    }
}

[download]

So how about emulating local using alias: 

use Data::Alias       qw( alias );
use Object::Destroyer qw( );

sub lambda {
    my $f = $_[1];
    my $xr = \$_[0];
    return sub {
        alias my $temp = $$xr;
        alias $$xr = $_[0];
        my $sentry = Object::Destroyer->new(
            sub { alias $$xr = $temp; }
        );
        return $f->();
    }
}

[download]

This should work whether $x is a lexical or a package variable. This should work whether $x is tied or not. In fact, it works better than local with tied variables and creates an alias unlike local.

Untested.

In reply to Re: Local for lexicals by ikegami
in thread Local for lexicals by JadeNB

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