Yes, executing that loop only called each once. But if after that loop you put a second loop that calls each, then that second loop will get a second pair out of the hash. Or if you try to iterate through with a while/each loop, you'll get every pair except the one already consumed in the for loop.

In other words the hash has been left in a potentially bad state.

In reply to Re^3: What is happening ? by tilly
in thread problem using foreach and each with hash ref by vinoth.ree

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