No. The only way chomp would remove two characters is if $/ was two characters long, and $/ is \n by default in Windows.

>ver Microsoft Windows XP [Version 5.1.2600] >perl -le"print length $/" 1 >perl -le"$,=' '; print map { uc unpack 'H*', $_ } $/=~/./sg" 0A

The reason this isn't a problem is that the PerlIO layer :crlf is used by default in Windows, and that layer converts CRLF to LF on read and LF to CRLF on write.

>>foo echo foo >debug foo -rcx CX 0005 : -d100 l5 0B0B:0100 66 6F 6F 0D 0A foo.. -q >perl -le"print length <>" foo 4 >perl -le"$,=' '; print map { uc unpack 'H*', $_ } <>=~/./sg" foo 66 6F 6F 0A

Builds of Perl without PerlIO (i.e. before 5.8) use the underlying C library, and it does the same thing.


In reply to Re^2: Length and Chomp ?? by ikegami
in thread Length and Chomp ?? by snape

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