Update: Too early in the morning

The . operator is the string concatenation operator, so @array . "\n" stringifies @array and adds "\n" to the end, which returns scalar(@array) . "\n", i.e. the count of elements in @array and a "\n".

@array "\n" doesn't appear to be valid syntax, how are you using it?
See perlop for more information on Perl Operators.

In reply to Re: difference between @array."\n" and @array "\n" by james2vegas
in thread difference between @array."\n" and @array "\n" by NileshJ

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