Consider the following 
sub subby(&\@\@)
{
 my ($coderef, $listA, $listB) = @_;

 my @result;
 .. logic .. 

 @result;
}

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I can call this fine using the following - 
my @subset = subby { .. logic .. } @A, @B;

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However, if I try to call it like this 
my @subset = subby { .. logic .. } @A, grep { .. logic .. } @B;

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I get this -> 
Type of arg 3 to main::subby must be array (not grep iterator) at ./te
+st line 36, near "@B;"

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This yields the same error 
my @subset = subby { .. logic .. } @A, (grep { .. logic .. } @B);

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Any ideas on how to get around this?

In reply to "not grep iterator" error by toddfreed

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