my %src = ( 0=>'a', 1=>'b', ... );

my ($s,$e) = (5,10);

my %dst;
@dst{ $s..$e } = @src{ $s..$e };

[download]
It's really weird that you're using hashes here and not arrays. It's a really inefficient and trickier way of storing ordered results. If you did switch to an array, the above would look like 
my @src = ( 'a', 'b', ... );

my ($s,$e) = (5,10);

my @dst = @src[ $s..$e ];

[download]

In reply to Re: A hash of a range of another hash by ikegami
in thread A hash of a range of another hash by Anonymous Monk

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