No it hasn't. You seem to be confusing Foo with the anonymous sub

  1. BEGIN { ... } is compiled.
    1. my $x = 12345; is compiled.
    2. *Foo = sub(){ $x }; is compiled.
  2. BEGIN { ... } is executed.
    1. my $x = 12345; is executed.
    2. *Foo = sub(){ $x }; is executed. ⇐ &Foo is declared and defined here.
  3. print Foo() is compiled. ⇐ &Foo is known to be constant.
  4. [ Execution phase starts ]
  5. print 12345 is executed.

vs

  1. { ... } is compiled.
    1. my $x = 12345; is compiled.
    2. *Foo = sub(){ $x }; is compiled.
  2. print Foo() is compiled. ⇐ &Foo is implicitly declared and called as a plain sub here.
  3. [ Execution phase starts ]
  4. { ... } is executed.
    1. my $x = 12345; is executed.
    2. *Foo = sub(){ $x }; is executed. ⇐ &Foo is defined here.
  5. print &Foo() is executed.

In fact, the prototype is always completely ignored if the subroutine call is compiled before the prototype is added. 

*Foo = sub($) { print "$_[0]\n" };
sub Bar($) { print "$_[0]\n" }

my @array = qw( a b c );
Foo(@array);  # a
Bar(@array);  # 3

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In reply to Re^5: Inlining a "lexically-scoped scalar which has no other references" by ikegami
in thread Inlining a "lexically-scoped scalar which has no other references" by LanX

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