Ok I almost understand it now.

It's hard to see s/this/that/ as an opperator! Because, err ... it looks like an expression, just like 3 + 4 is, in the following which prints 7 as expected.

my $var;
print $var = 3 + 4 . "\n"; # Just for illustration!

[download]

Please do be a little more forgiving of beginners ;-) The print example code is just a clear way of illustrating my confusion. Here is the original code snippet with the incorrect line commented and the correct one as per your helpful explanations.

foreach (keys %{$ref_cookie}) {
# push(@{$self->{cookies}}, {$_=~s/^-//}, $ref_cookie->{$_}});
  push @{$self->{cookies}} , do{$_=~/^-(.*)/;$1}, $ref_cookie->{$_});
}

[download]

Thanks

In reply to Re^2: Inline substitution regex by bradcan
in thread Inline substitution regex by bradcan

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