Not really. can checks if a method exists, not if it has been defined.
sub foo;
print( __PACKAGE__->can('foo') ?1:0,"\n"); # 1
print( defined(&foo) ?1:0,"\n"); # 0
print( exists(&foo) ?1:0,"\n"); # 1
To check if an inherited method is defined, you need
my $method_ref = __PACKAGE__->can('foo');
print( $method_ref && defined(&$method_ref) ?1:0,"\n");
That's said, it's quite likely that the OP should have been using exists and that can will do the trick by itself.
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