True.

You'd only need my algorithm if you wanted to express the integer in a base other than 16 (or 8).

use bigint; 

my @digits=map chr,(0x30..0x39,0x41..0x5d);
my $base = 22;
my $n = 123456789123456;
my $h;
while($n > 0){
    $h .= $digits[ $n % $base ];
    $n /= $base;
}
print scalar reverse $h';

[download]
Result is 4E5G93GHBE8.

In reply to Re^4: long integer to hexadecimal conversion by kikuchiyo
in thread long integer to hexadecimal conversion by perl_fan

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