Actually I don't see you getting a 'top 10' of anything anywhere in that code. If I understand your problem I'd solve it something like:

#!/usr/bin/perl

use strict;
use warnings;

my %hostsData = (
    'blah1' => [132, 208, 146, 53, 77, 295, 33, 205, 8, 167, 147, 6, 8
+7, 261, 158],
    'blah2' => [40, 220, 222, 182, 276, 17, 128, 126, 102, 228, 247, 1
+69, 86, 182, 229],
    'blah3' => [223, 175, 248, 285, 13, 235, 242, 187, 48, 40, 96, 114
+, 293, 133, 20],
    'blah4' => [83, 125, 46, 170, 208, 292, 116, 49, 2, 246, 73, 65, 1
+80, 265, 48],
    'blah5' => [59, 73, 256, 174, 235, 114, 136, 217, 204, 98, 278, 22
+1, 78, 287, 42],
);
my %top10s;

for my $host (keys %hostsData) {
    # Generate list of top 10 items for a host
    $top10s{$host} = [@{[reverse sort {$a <=> $b}  @{$hostsData{$host}
+}]}[0 .. 9]];
}

my @top10;

for (1 .. 10) {
    # Pick next top item
    my $topHost;
    my $topValue;

    for my $host (keys %top10s) {
        next if ! @{$top10s{$host}};

        next if defined $topHost && $topValue >= $top10s{$host}[0];

        $topHost = $host;
        $topValue = $top10s{$host}[0];
    }

    last if ! defined $topHost;

    push @top10, [$topHost, $topValue];
    shift @{$top10s{$topHost}};
}

print "$_->[0]: $_->[1]\n" for @top10;

[download]

Prints:

blah1: 295
blah3: 293
blah4: 292
blah5: 287
blah3: 285
blah5: 278
blah2: 276
blah4: 265
blah1: 261
blah5: 256

[download]

If that isn't what you were looking for how about you write a sample script that doesn't need web or database access to demonstrate your problem and resubmit your question?

True laziness is hard work

In reply to Re: How do I sort top 10 for multiple hosts? by GrandFather
in thread How do I sort top 10 for multiple hosts? by kdmurphy001

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