How does "treated like any vulgar scalar" differ from "no longer treated specially"?Sorry, you're right—aside from the fact that the former is funny and the latter isn't, not at all. :-)
I remembered only “commutativity breakage” and “vulgar scalar”, and completely forgot about the bit in between:
code references are no longer treated specially when appearing on the left of the ~~ operatorso that I didn't realise what it was that you were claiming was redundant.
In reply to Re^5: Perl 5.11.0 now available
by JadeNB
in thread Perl 5.11.0 now available
by Anonymous Monk
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