I tend to agree with the suggestions of others that the second regex in the chomped <STDIN> section of the OPed code is simply failing to match, and the previous value of  $1 is persisting.

Try inserting the statement
    print qq{\$1 reset: '$1'} if 'foo' =~ /(foo)/;
between the first and second regex in that section and seeing what happens. If the second  'ZZZ' becomes  'foo' you will know what is happening (although not why the second regex fails to match, which I cannot understand myself).


In reply to Re: perl pattern match for end of string using STDIN and chomp by AnomalousMonk
in thread perl pattern match for end of string using STDIN and chomp by cbolcato

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