First, most likely, you wouldn't be passing in a single array; most people in this case would use refernces to pass the arrays in and forget about having to worry about where one ends and the other begins.

Additionally, there's no reason to invoke a regex here when a simple neq would do the job. Something like this would be better: 

sub exclude {
   my ($a, $b) = @_;
   for (1..@$a) {
      my $i = shift @$a;
      push @$a, $i if ( !grep { $_ eq $i } @$b );
   }
   @$a; 
}

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Of course, with perl, TIMTOWTDI...
Dr. Michael K. Neylon - mneylon-pm@masemware.com || "You've left the lens cap of your mind on again, Pinky" - The Brain

In reply to Re: exclude all members of @a from @b by Masem
in thread exclude all members of @a from @b by zane

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