The problem is for($i;... as nothing is happening to $i there. Change it to $i=0, warning should go away. It is a little weird that the warning appears on the last line of the for-loop, but that's probably how the parsing worked out.

HTH,
SSF

In reply to Re: Useless use of private variable in void context by sflitman
in thread Useless use of private variable in void context by okarmi

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