Try the function isa, as described in perlobj. The test would be 
sub foo {
   isa( $_[0], 'HASH' ) ? _foo_hash( $_[0] ) : _foo_scalar( $_[0] );
}

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Dr. Michael K. Neylon - mneylon-pm@masemware.com || "You've left the lens cap of your mind on again, Pinky" - The Brain

In reply to Re: Is it a scalar or a hash? by Masem
in thread Is it a scalar or a hash? by DrZaius

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