Actually i came up with the following:

I done this by negation and using the values for the upper left lower right respectively for both sqares.

square #1: upper left= x1,y1 ; lower right= x2,y2
square #2: upper left= x3,y3 ; lower right= x4,y4

return !(x2 < x3 || x1 > x2 || y2 > y3 || y1 < y4)

[download]
Hope my logic is right...can someone confirm?

Thanks,
Total Newbie

In reply to Re^2: Checking if squares intersect by Anonymous Monk
in thread Checking if squares intersect by Anonymous Monk

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