Ah, still more fuel for my wild speculation! You have indicated the
deparse-ing of
tied( sub {}->() ), which is just as I expected; but I went back and checked the
deparse-ing of
tied sub {}->(), and it looks the same to me:
$ perl -MO=Deparse,-p -e 'tied sub {}->()'
tied({sub {
}
}->());
-e syntax OK
I had assumed from the (ahem) reference to reference constructors that
tie was gobbling up the
sub {} before
->() could get at it, but that's obviously not the case. So: Since they
deparse identically, why do
tied sub {}->() and
tied( sub {}->() ) give different error messages?
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