-MO=Deparse shows print "MATCHED\n" if @list = !('foo bar baz' =~ /\bbar\b/);, which explains your observation. Which I read as an implicit "cast" from scalar not to list context for the assignment, similar to @list=5 implying @list=(5).

(initially I thought about about =~ possibly being used in list context as well, but that's nonsensical).

I've problems imagining sensible semantics for an alternate implementation of list context (matching substrings) on a non-match operator like !~, so the current solution above seems sanest to me.

However man perlop could be more explicit: Binary "!~" is just like "=~" except the return value is negated in the logical sense. Elsewhere, same document: When there are no parentheses in the pattern, the return value is the list "(1)" for success. With or without parentheses, an empty list is returned upon failure.

cu & HTH, Peter -- hints may be untested unless stated otherwise; use with caution & understanding.

In reply to Re: regex in list context by jakobi
in thread regex in list context by azadian

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