%h = qw[ a 2 b 4 c 2 d 1 e 1 f 2 g 4 h 3 ];;

pp \%h;;
{ a => 2, b => 4, c => 2, d => 1, e => 1, f => 2, g => 4, h => 3 }

++$f{ $_ } for values %h;;

pp \%f;;
{ 1 => 2, 2 => 3, 3 => 1, 4 => 2 }

[download]

If you need the zero counts also, the initialise the frequency hash first: 

$f2{ $_ } = 0 for 0 .. 5;;

++$f2{ $_ } for values %h;;

pp \%f2;;
{ "0" => 0, 1 => 2, 2 => 3, 3 => 1, 4 => 2, 5 => 0 }

[download]
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In reply to Re: count frequency of occurence.... by BrowserUk
in thread count frequency of occurence.... by cthar

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