Oh! I see now. This:
s/\A\s+//, s/\s+\z// for my @r = @_;
is the same as
my @r = @_; s/\A\s+//, s/\s+\z// for @r;
Thanks!
In reply to Re^2: How does this code work? (from "Perl is Unix")
by Anonymous Monk
in thread How does this code work? (from "Perl is Unix")
by Anonymous Monk
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