You may be right about bottom-up evaluation of SK expressions. Larger terms must be treated as first-class objects to be passed around, etc.

But we both missed the obvious way to just use "plain" regex substitutions to simulate Turing-completeness: unrestricted (type-0) grammars. They are basically defined as the repeated evaluation of plain regex substitutions, and are Turing-complete. A universal TM converted to a type-0 grammar will only have a finite number of substitution rules, and you can simulate it with a substitution + finite lookup table (or a finite # of separate s/// statements).

blokhead

In reply to Re^3: Turing completeness and regular expressions by blokhead
in thread Turing completeness and regular expressions by JadeNB

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