There's no need to quote. Regular expressions don't interpolate arrays where the name is a punctuation symbol: 
say qr|\A(.+)\Q@@/|;
__END__
(?-xism:\A(.+)\@\@\/)

[download]
But in general, if you use single quotes as delimiter, no interpolation will happen: 
my @a = ("foo");

say  "foo"   =~ m |@a| ? 'Found "foo"' : 'Did not find "foo"';
say  "foo"   =~ m '@a' ? 'Found "foo"' : 'Did not find "foo"';
say  'bar@a' =~ m |@a| ? 'Found "@a"'  : 'Did not find "@a"';
say  'bar@a' =~ m '@a' ? 'Found "@a"'  : 'Did not find "@a"';
__END__
Found "foo"
Did not find "foo"
Did not find "@a"
Found "@a"

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In reply to Re: regular expression with @@/ by JavaFan
in thread regular expression with @@/ by jim_neophyte

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