Assuming you are only applying this to numbers of the form \d*.?\d* (numerals 0-9 with 0 or 1 decimal point), you can do this fairly simply with the $ metacharacter, which matches the end of a string (Regular Expressions). Your final expression might look like this:

#!/usr/bin/perl use strict; use warnings; my @numbers = qw(1230.1200 10332.0120 1200); foreach my $number (@numbers) { $number =~ s/(\.\d*?)0*$/$1/ } print join "\n", @numbers;

In reply to Re: substitution "0" in decimals by kennethk
in thread substitution "0" in decimals by Sun751

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