Be aware though that forcing numericification does lose precision, as .12 cannot be representated by an exact binary representation: 
perl -wE '$d1 = "1230.1200"; $d1 = $d1 + 0; printf "%.20f\n", $d1'
1230.11999999999999999556

[download]
It may not matter for the OP, but at least he should be made aware of when using this trick.

In reply to Re^2: substitution "0" in decimals by JavaFan
in thread substitution "0" in decimals by Sun751

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