You cannot pass a variable to a function (whether it be by value or by reference) and know its name at the same time. You can, however, pass a string that represents the name of the variable, and then evaluate the string to get its value.

#! perl -w

use strict;

use vars qw/$foo/;
$foo = 3;
my $bar = 4;

sub reality_test {
    my ( $var_name , $bound ) = @_;
    my $var = eval $var_name;
    die "$var_name is not syntactically correct: $@\n" if $@;

    print "'$var_name' was less than allowed\n"
        if $var < $bound;
}

reality_test( '$foo' , 10 );
reality_test( '$bar' , 10 );

[download]

That's a sort of a weird thing to do, but hey, what ever gets you through the night...

The trouble is you have to use the non-standard convention of passing the variable name in a string. You may remember to do this, but you will not endear yourself to your coworkers. If you forget to pass a string, and pass a variable instead, it still works correctly, but the script no longer prints out the name of the variable but rather its value.


--
g r i n d e r

In reply to Re: Can Perl add single quotes? by grinder
in thread Can Perl add single quotes? by tenya

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